Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. (Surface tension of soap solution = 0.03 Nm –1 )
Text Solution
Verified by ExpertsThe correct answer is:
D
W = T 
A
= 0.03 (2 × 4 π × (5 2 – 3 2 ) 10 –4 = 24 π (16) × 10 –6
= 0.384 π × 10 –3 Joule 0.4 π mJ
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